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-11x=6+5x^2
We move all terms to the left:
-11x-(6+5x^2)=0
We get rid of parentheses
-5x^2-11x-6=0
a = -5; b = -11; c = -6;
Δ = b2-4ac
Δ = -112-4·(-5)·(-6)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*-5}=\frac{10}{-10} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*-5}=\frac{12}{-10} =-1+1/5 $
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